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(2^2x)(2^(x+1))=(2^5x)/(2^9)
We move all terms to the left:
(2^2x)(2^(x+1))-((2^5x)/(2^9))=0
We get rid of parentheses
2^2x(2^(x+1))-2^5x/2^9=0
We multiply all the terms by the denominator
(2^2x(2^(x+1)))*2^9-2^5x=0
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